Evaluate the integral: (Question will be posted ASAP)
\[\int\limits_{2}^{4}\frac{ dx }{ x(\ln x)^2 }\]
put t=ln x
use u-substitution, try setting u=lnx
then dx/x = dt
I'm confused because I managed to get to 1/ln2 -1/ln4 using that method but the answer in my booklet is \[2\sqrt{\ln(secx+tanx)}+c\]
\[\int\limits \frac{dt}{t^2} = ??\]
Haha I know right? guess my answer booklet made a mistake. Alright, hartnn, can you show me your steps for this? so that I can compare it mine :)
You should show your steps first so that @hartnn can compare if he or she has done it right or not..
@lightchaste , your answer is correct
yup, sorry 1/ln2 -1/ln4 is correct.......
oh, really? haha. Should that be the final answer?
it can be simplified to 1/ln 4
yeaaaahhh how do you do just that?? :)
ln 4 = 2 ln 2
could u get 1/ln 4 now?
yeah! I got it :D thank you sooo much :)
welcome :)
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