Compute (fog)(x) when f(x) = (4x^2+14x+10) and g(x) = (2/(x-3))
I guess I get stuck at the place where I stopped working. Should I be trying to find an LCD now? I tried that on an earlier attempt of this problem, and it didn't go so well.
No, you're right, now multiply both the numerator of the two latter fractions by something that will allow you to sum the fractions (with a common denominator).
*both the numerator and the denominator
Right, I multiply the numerator and denominator of the second term by (x-3) and the then the third term by (x-3)^2, right?
Yessir/ma'am
After a little more work, I'm now at [2(5x-11)(x-1)]/(x-3)^2
Looks right to me! I didn't go THOROUGHLY through it, but it seems like it's right. At least your manipulation and the steps you're taking are right.
Ok, thanks, Wolf.
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