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OpenStudy (anonymous):
How many moles and how many grams of NaCl are present in 250cm^3 of a 0.500M NaCl solution?{Molar mass of NaCl = 58.44g}
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OpenStudy (anonymous):
@mayankdevnani
OpenStudy (anonymous):
@mathslover
OpenStudy (mayankdevnani):
\[mean\] \[250cm ^{3}\]
OpenStudy (anonymous):
yeah
mathslover (mathslover):
hmn wait...
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OpenStudy (anonymous):
ok
mathslover (mathslover):
ok so the unit of density is = ?
mathslover (mathslover):
just tell me this... so that i can proceed @KingAditya
mathslover (mathslover):
kg m^{-3}
OpenStudy (anonymous):
kg/m^3
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mathslover (mathslover):
right...
mathslover (mathslover):
unit of volume = cm^3 ( CGS )
OpenStudy (anonymous):
yeah
mathslover (mathslover):
Ok so now... what does M denote ? Molar...?
OpenStudy (anonymous):
mole
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OpenStudy (anonymous):
m waiting
OpenStudy (mayankdevnani):
m answering....
OpenStudy (mayankdevnani):
plz wait until i give you correct answer...
OpenStudy (anonymous):
ok @mayankdevnani
OpenStudy (anonymous):
can any one help me
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OpenStudy (anonymous):
@ParthKohli
OpenStudy (australopithecus):
250cm^3 = mL
OpenStudy (australopithecus):
0.250L = 250mL
\[Molarity = \frac{MolesOfSolute}{LitersOfSolution}\]
OpenStudy (australopithecus):
0.500M = x mole/0.250L
0.500M*0.250L = 0.125mol
then use the following formula to solve for Grams:
\[Moles = \frac{Grams}{MolecularMass}\]
mathslover (mathslover):
\[\large{0.125=\frac{grams}{58.44}}\]
just multiply 0.125 * 58.44
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OpenStudy (australopithecus):
yup yup
mathslover (mathslover):
though good work @Australopithecus ....
OpenStudy (anonymous):
thnx @australopithecus nd @mathslover
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