Geometric Series. 2+4+8...n/4+n/2+n.
I have never done one of these summations before.
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OpenStudy (anonymous):
use the formula
a(r^n-1)/r-1
where r is the common ratio
and a is the first term of the series
OpenStudy (anonymous):
so, a(2^n-1)/2-1
OpenStudy (anonymous):
2(2^n-1)/2-1
OpenStudy (anonymous):
yes then substitute value of n
OpenStudy (anonymous):
ok, but what is n?
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OpenStudy (anonymous):
it is the number of terms u are including in ur GP
OpenStudy (anonymous):
I dont know how many terms there are.
OpenStudy (anonymous):
but if u dont know how many terms are there then leave it in terms of n
and ur sum WILL depend on the value of n
OpenStudy (anonymous):
that is quite logical
OpenStudy (anonymous):
ok, if i simplify that equation I get -2^n
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OpenStudy (anonymous):
is that the answer?
OpenStudy (anonymous):
well, its 2n-1,from the answer booklet.
OpenStudy (anonymous):
2n-1 doesn't seem correct. The sum of first 2 terms (n=2) is 6. But, 2n-1 would give 3!! The correct answer is 2(2^n - 1). Another clue is that the sum increases exponentially, so there ought to be an exponential term in the answer!
OpenStudy (anonymous):
you can test out your answer ex: 3rd term = n = 3, so 2n-1 would equal 5, which is wrong. 2(2^n-1) is the correct answer