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the velocity time graph of a ball of mass 25g moving on a road is as given below a)how much force does the road exert on the ball to bring it to rest. b)what is the direction of force exerted by the road.?
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13th question in the given QP
Force= mass* aceleration acceleration = dV/dt= slope of velocity - time graph by this you will have retardation= 2.5m/s^2 therefore force= 0.025*2.5=0.0625N
now direction of force exerted on ball will be opposite to the direction of motion of ball
F=mass * acceleration Mass is given = 25 g = 0.025 kg Acceleration would be the gradient of the graph since it is a velocity vs. time graph and m/s/t = m/s/s = the units for acceleration.
acceleration=(0-10)/(4-0)=-2.5m/s^2 that is retardation
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