the velocity time graph of a ball of mass 25g moving on a road is as given below
a)how much force does the road exert on the ball to bring it to rest.
b)what is the direction of force exerted by the road.?

Question

the velocity time graph of a ball of mass 25g moving on a road is as given below
a)how much force does the road exert on the ball to bring it to rest.
b)what is the direction of force exerted by the road.?

anonymous · Answer

13th question in the given QP

ghazi · Answer

Force= mass* aceleration
acceleration = dV/dt= slope of velocity - time graph 
by this you will have retardation= 2.5m/s^2
therefore force= 0.025*2.5=0.0625N

ghazi · Answer

now direction of force exerted on ball will be opposite to the direction of motion of ball

anonymous · Answer

F=mass * acceleration 
Mass is given = 25 g = 0.025 kg
Acceleration would be the gradient of the graph since it is a velocity vs. time graph and m/s/t = m/s/s = the units for acceleration.

ghazi · Answer

acceleration=(0-10)/(4-0)=-2.5m/s^2 that is retardation