Question

If x^2/y is an integer, but x/y is NOT an integer, which of the following could be values of x and y?

x=1 y=1

x=3 y=2

x=4 y=2

x=6 y=4

x=9 y=3

Answer 1

Well we can rule out the first, third and fifth option because those x/y give integers.
Try substituting the remaining options into x^2/y and see which one gives you an integer.

Answer 2

so is it x=3 y=2?

Answer 3

it's a wrong question... all options are integers or rational numbers.......if irrational numbers are given so, it can be possible...

Answer 4

@mitchelsewbaran

Answer 5

No it would be x=6, y=4 because 6^2=36 and 36/4 gives you 9 which is a whole number

Answer 6

why?? 9/1 is rational number

Answer 7

@Shane_B I don't understand why I'm wrong? 36/4 gives you 9 which is an integer and 6/4 does not give you an integer

Answer 8

Wait...I'm retarded. I read the integer/non-integer parts question backwards :/

@sedighn: You are correct.

Answer 9

@Shane_B Haha don't worry about it :) I thought I was going crazy too

Answer 10

I read it too fast. Actually, even if I read the terms backwards I was wrong!

I guess I saw the 3^2/2 and jumped to the assumption that had to be the one that resulted in a non-integer (since I read it backwards)...and didn't even consider the second part of the question (which would have probably made me realize my error) :)

Answer 11

True and I tend to over-think simpler questions because I'm always expecting a catch :P