Can anyone help me with finding the domain and range for this quadratic equation y = –x^2 – 14x – 52?
\[b^2 -4ac \geq 0\]
What..?
Take it to the completed square form
How?
Factorize it
y = –x^2 – 14x – 52 = -(x^2+14x)-52 =-(x^2+2*x*7+7^2-7^2)-52 = -{(x+7)^2-49}-52 =-(x+7)^2-3
thats the completed square form
Now, domain is x E R.......
For range, (x+7)^2>=0 -(x+7)^2<=0 -(x+7)^2-3<=-3 y<=-3
got it?
I always look at the graphs when determining the domain and range
domain is all real numbers range is all numbers less than and equal to -3 just like sauravshakya stated
use the above link if you do not own a graphing calculator
Domain is R becoz...there is no...Restrictions...)) in the given equation
yes and domain is all real numbers because all of the x's are being used on the number line to plot the function
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