Question

Geometry problem, in comments, really short!

Answer 1

Remember the identity that:
\[
\cos^2(\theta)+\sin^2(\theta)=1
\]Rearranging gives us:
\[
\sin(\theta)=\sqrt{1-\cos^2(\theta)}
\]Try using that to figure out one from the other.

Answer 2

I got \[\sqrt{29}/7\]

Answer 3

no it would be 3/7

Answer 4

I'm getting
\[
\sin \theta=\frac{3}{7}
\]

Answer 5

ok thank you

Answer 6

agreed, but plus or minus in front

Answer 7

\[\sin \theta= \sqrt{1-40/49}= \sqrt{\frac{ 49-40 }{ 49 }}=\sqrt {\frac{ 9 }{ 49 }}=\frac{ 3 }{ 7 }\]

Answer 8

I felt someone had to say that, but, yes.