Question

* The average value of an even function is (-ve ,+ve, infinite, none)

Answer 1

Well that depends really... The average value of its entire domain?

Answer 2

I can think of an even function which has a finite average value, and I can think of one that has an infinite one...

Answer 3

If you were talking about an odd function then it'd be easy...

Answer 4

This was a question in my exam and i dnt knw how to figure it out..

Answer 5

What about an odd functon??

Answer 6

For an odd function it would be 0, since on the other side of the y axis you have negative values.

Answer 7

so the best ans is none...??

Answer 8

yes, I guess.

Answer 9

But to your previous question:
For an odd function \(f\), we know that \(f(x)=-f(-x)\). As such, the average value (assuming \(f\) exists over all \(\mathbb R\)) is\[\lim_{a\rightarrow\infty}\frac{1}{2a}\int_{-a}^af(x)dx=\lim_{a\rightarrow\infty}\frac{1}{2a}(\int_0^af(x)dx+\int_{-a}^0f(-x)dx))\]\[=\lim_{a\rightarrow\infty}\frac{1}{2a}(\int_0^af(x)dx+\int_{-a}^0-f(-x)dx)\]Let \(u=-x\)\[=\lim_{a\rightarrow\infty}\frac{1}{2a}(\int_0^af(x)dx-\int_{0}^af(u)du)=0\]