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* Logx5=4log5(X) find solution
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use base change formula
\[5^{\pm \frac{ 1 }{ 2 }}\]
Kindly solve it...
log5/logx= 4(log x/log5)
is it \[\log_{}x^5=4\log_{}5x \] ?
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\[\log^25=4*\log^2x....2\log5=8logx .......x=1/4\log5\]
\[logx= \frac{ 1 }{ 4 }\log 5\]
\[x=5^{1/4}\]
how did u get log x=1/4 log5 from x=1/4 log 5 ??
well that was a typing mistake my apology :)
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after that i haven't repeated it
then x won't be 5^(1/4)
yes it will be
but x=1/4 log 5,how can it be 5^1/4
it can be atmost log(5^(1/4))
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\[\log x= \frac{ 1 }{ 4 } \log5......\log x =\log 5^{1/4}....x=5^{1/4}\]
ok.
:)
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