In the figure below, line AB is tanget to the circle with center E at point D. If the length of minor arc DC is 7π and line EC=21, what is the measure of angle BDC?
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OpenStudy (anonymous):
OpenStudy (anonymous):
ok so do you know what is the angle EDB ?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
it is 90 degrees .. angle between tangent and radius is 90 degrees
OpenStudy (anonymous):
do you think that now you can solve it maybe ?
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OpenStudy (anonymous):
does involve any trig?
OpenStudy (anonymous):
i think so
OpenStudy (anonymous):
if so, i'm new to to trig
OpenStudy (anonymous):
ok what kind is the triangle DCE ?
OpenStudy (anonymous):
equilateral
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OpenStudy (anonymous):
are u able to read the diagram i attached here? i have pretty bad handwriting
OpenStudy (anonymous):
so it means that angle EDC = ECD
OpenStudy (anonymous):
and it means that DE = EC
OpenStudy (anonymous):
do you know the law of cosines ?
OpenStudy (anonymous):
c^=a^2b^2-2ab cos(C)
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OpenStudy (anonymous):
good .. now we want to find EDC
sine if we subtract it from 90 we will get the requested angle..
so use this law for this angle
OpenStudy (anonymous):
c^2= 7π^2-21^2-2 (7π)(21) cos (90º) ?
OpenStudy (anonymous):
c = 21 (we got it from the fact that it is equilateral)
OpenStudy (anonymous):
and notice its not 90 degrees..
OpenStudy (anonymous):
the whole angle EDB = 90
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OpenStudy (anonymous):
but EDC is not 90 .. call it C and solve the equation for cos(C)
OpenStudy (anonymous):
we're looking for angle BDC
OpenStudy (anonymous):
right .. but if we will have EDC
we will be able to subtract it from 90 and get BDC
OpenStudy (anonymous):
since BDC + EDC = EDB = 90
OpenStudy (anonymous):
so how do we solve this equation?
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OpenStudy (anonymous):
21^2= 7π^2+21^2-2 (7π)(21) cos (C) right ?
OpenStudy (anonymous):
tell me if you agree with it
OpenStudy (anonymous):
ok. my previous equation applying the cosines law was wrong. and yes, i agree :)
OpenStudy (anonymous):
good .. so now isolate cos(C) and get the angle C
OpenStudy (anonymous):
solve for cos(C)?
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OpenStudy (anonymous):
yes and eventually solve for C (by using arccos )
OpenStudy (anonymous):
C = π/42?
OpenStudy (anonymous):
mm i dont think so :
cos(C) = 7pi / 42
so
C is about 58.43
OpenStudy (anonymous):
so the answer is like 60 degrees?
OpenStudy (anonymous):
for C
.. but we need 90 - C remember ?
so the answer for the question is about 30 or to be more accurate 31.57
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OpenStudy (anonymous):
the closest is 30, bro?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
do you understand why we subtract C (60) from 90 and got 30 ?
OpenStudy (anonymous):
thnx, bro!
OpenStudy (anonymous):
yw :)
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