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Mathematics 6 Online
OpenStudy (anonymous):

In the figure below, line AB is tanget to the circle with center E at point D. If the length of minor arc DC is 7π and line EC=21, what is the measure of angle BDC?

OpenStudy (anonymous):

OpenStudy (anonymous):

ok so do you know what is the angle EDB ?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

it is 90 degrees .. angle between tangent and radius is 90 degrees

OpenStudy (anonymous):

do you think that now you can solve it maybe ?

OpenStudy (anonymous):

does involve any trig?

OpenStudy (anonymous):

i think so

OpenStudy (anonymous):

if so, i'm new to to trig

OpenStudy (anonymous):

ok what kind is the triangle DCE ?

OpenStudy (anonymous):

equilateral

OpenStudy (anonymous):

are u able to read the diagram i attached here? i have pretty bad handwriting

OpenStudy (anonymous):

so it means that angle EDC = ECD

OpenStudy (anonymous):

and it means that DE = EC

OpenStudy (anonymous):

do you know the law of cosines ?

OpenStudy (anonymous):

c^=a^2b^2-2ab cos(C)

OpenStudy (anonymous):

good .. now we want to find EDC sine if we subtract it from 90 we will get the requested angle.. so use this law for this angle

OpenStudy (anonymous):

c^2= 7π^2-21^2-2 (7π)(21) cos (90º) ?

OpenStudy (anonymous):

c = 21 (we got it from the fact that it is equilateral)

OpenStudy (anonymous):

and notice its not 90 degrees..

OpenStudy (anonymous):

the whole angle EDB = 90

OpenStudy (anonymous):

but EDC is not 90 .. call it C and solve the equation for cos(C)

OpenStudy (anonymous):

we're looking for angle BDC

OpenStudy (anonymous):

right .. but if we will have EDC we will be able to subtract it from 90 and get BDC

OpenStudy (anonymous):

since BDC + EDC = EDB = 90

OpenStudy (anonymous):

so how do we solve this equation?

OpenStudy (anonymous):

21^2= 7π^2+21^2-2 (7π)(21) cos (C) right ?

OpenStudy (anonymous):

tell me if you agree with it

OpenStudy (anonymous):

ok. my previous equation applying the cosines law was wrong. and yes, i agree :)

OpenStudy (anonymous):

good .. so now isolate cos(C) and get the angle C

OpenStudy (anonymous):

solve for cos(C)?

OpenStudy (anonymous):

yes and eventually solve for C (by using arccos )

OpenStudy (anonymous):

C = π/42?

OpenStudy (anonymous):

mm i dont think so : cos(C) = 7pi / 42 so C is about 58.43

OpenStudy (anonymous):

so the answer is like 60 degrees?

OpenStudy (anonymous):

for C .. but we need 90 - C remember ? so the answer for the question is about 30 or to be more accurate 31.57

OpenStudy (anonymous):

the closest is 30, bro?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

do you understand why we subtract C (60) from 90 and got 30 ?

OpenStudy (anonymous):

thnx, bro!

OpenStudy (anonymous):

yw :)

OpenStudy (anonymous):

ur reward is a medal

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