use elmination method to solve system of equations a+8b=17 a+3b=2
because the variable a already have the same coefficients you can just subtract the two equations (a+8b)-(a+3b)=17-2 a+8b-a+3b=15 11b=15 b=15/11
then just substitute b with 15/11 to solve for a
ok thanks
how did you get 17
oh i see
17 is the answer of the first equation a+8b=17 2 is the answer of the second equation a+3b=2
so the subtration is used to elminate
yes, it the equations were a+8b=17 -a+3b=2 then you would use addition to eliminate the a
i see
how do I get 17 in the equation when replacing 15/11 for b
a+8(15/11)=17 a=17-120/11 a=67/11
am confused because for my answer choices it has a. one solution type ordered pair b. many solutions c. no solutions
wait that's wrong, i think i did my math wrong
ahh i see, i subtracted wrong, when you subtract it should be (a+8b)-(a+3b) a+8b-a-3b 5b=17-2=15 b=3
substitute b with 3 in one of the original equations a+3(3)=2 a+9=2 a=-7 check to see if it works in the first equation -7+8(3)=17 -7+24=17 17=17
good?
yea :)
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