What is the integral of f(x)=√(x)/√(1=x^2)?
√(1=x^2) ???
\[\int\limits_{}^{}\frac{\sqrt{x}}{\sqrt{1-x^2}}dx\] @byuckert is this your question?
Yes yes yes. I apologize for the typo.
do you know trig substitution?
Actually, it is a plus, not a minus.
I know that it is somewhat in the form of sinh^-1(x), but I don't know what to do with the numerator.
again, do you know trig substitution? it kinda looks like a trig substitution problem
No, we have not covered that.
meh ok wolfram alpha integrator gives a weird answer anyways trig substitution in a nutshell \[1+\tan^2\theta=\sec^2\theta\] \[\sin^2\theta+\cos^2\theta=1\] you need to know those 2 basically if 1+x^2 ever appears as a denominator make the substitution \[x=\tan\theta\] \[dx=\sec^2\theta d\theta\] \[\int\limits_{}{} \frac{\sqrt{\tan \theta}}{\sqrt{1+\tan^2 \theta}}\sec^2\theta d\theta\] ok this looks messy so im probably missing but yes thats trig substitution
I tried Wolfram, as well, and all it did was confuse me more. Thank you very much for taking the time to do this. So from there how are you able to solve the integral?
not really, \[\int\limits_{}{}\sqrt{\tan \theta}\sec \theta d\theta\] is what you would get if you simplified it integrate by parts? it just looks horrible to integrate, and im hoping i made a mistake somewhere
Could you do another substitution here? u-sub or similar?
I tried a u-sub in every way that I found possible and, really, none seem to work.
@completeidiot, yeah I know we are definitely not supposed to be integrating by parts yet. I appreciate it though.
no closed form for this integral
I feel like you're right. Sometimes I question my teacher's awareness...
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