Question

Use the quadratic formula to find the real solutions, if any, to the equation.
x^2 + 2x - 5 = 0

Answer 1

I'm stuck at \[=\frac{ -2 \pm \sqrt{-5} }{ 2 }\]

Answer 2

for the equation \(ax^2+bx+c=0\) u have solutions
\[ \large x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \]

Answer 3

Mhmm o;

Answer 4

\[ \large b ^2-4ac=4-4(1)(-5)= \]

Answer 5

Look at my first comment xD

Answer 6

i did and i'm correcting u.

Answer 7

It's -5

Answer 8

OH.
it's 0.

Answer 9

so that means no solutions?

Answer 10

\[ \large 4-4(1)(-5)=4+20=24 \]

Answer 11

Oh, yeah. :c that was nooby sorry.

Answer 12

so
\[ \large x=\frac{-2\pm\sqrt{24}}{2} \]

Answer 13

What would you do about the -2 and 2?

Answer 14

\[ \large \sqrt{24}=\sqrt{6\cdot4}=2\sqrt{6} \]

Answer 15

\[ \large x=\frac{-2\pm2\sqrt{6}}{2}=-1\pm\sqrt{6} \]

Answer 16

Ohhh. So would the solutions be \[-1+\sqrt{6}, -1-\sqrt{6}\]

Answer 17

yes

Answer 18

Thank you so much!

Answer 19

u r welcome