Question

Select the counterexample that makes this conjecture false:
For any real number x, if x2 ≥1, then x ≥1.

Answer 1

take any negative number less than 1
say x=-2
x^2=(-2)^2=4
so x^2=4 > 1
but x= -2 < 1

Answer 2

so the answer comes to x=2

Answer 3

no,here u just need to give an counterexample.....
so i gave an example when x=-2

Answer 4

are there options?

Answer 5

yes x=1,x=1/4,x=2,x=-3

Answer 6

so there's x=-3
x^2=(-3)^2=9 >1
x=-3 <1

Answer 7

so it would be x=1

Answer 8

can you gave the exact sol.l. of this problem

Answer 9

how 1 ?
i showed u a counterexample with x=-3.

Answer 10

its x=-3

Answer 11

by differntial equatin solution