exact value of e^2x=-3
check your question.
Your exponential is not going to be non-positive. Forgive the double negative.
\[-3=e^{\log_e(-3)}=e^{\ln-3}\]
e^2x cannot equal a negative number
Complex numbers
i just looked at the answer in the back of the book and it says no solution your all right but how this is concluded i don't know, if anyone would like to shed some light on this please go ahead
\[e^{2x}=-3\] \[e^{iy}=cosy+isiny\] Call x=iy \[e^{i2y}=-3\] The imaginary part of \[e^{i2y}=0\] Therfore \[siny=0\] Thus\[y=\pi n\]
\[x=i\pi n\]
Okay, I'll give an overview of complex no.s
http://betterexplained.com/articles/a-visual-intuitive-guide-to-imaginary-numbers/ http://www.youtube.com/watch?v=2aQ1s1ioNWM and for e^iy=.... http://www.youtube.com/watch?v=qpOj98VNJi4
you can help me with Iny = 13x if you want
But to sum up- - Multiplying= scaling numbers - Multiplying by negative= scaling & flipping 180 degrees on the number line |dw:1346673982042:dw| So, it's almost as if when numbers multiply, they 'add' their 'angles', but positive numbers have 0 degrees, and negatives, 180 What squares to -1? -1 'has' 180 degrees if you measure 0 degrees as a number pointing rightwards on a number line. This question is the same as 'what angle adds twice to make 180?' obviously, 90 (or -90). So there is a number with '90 degrees', the square root of -1, which we call i. I can scale also, like normal negative numbers, so you can have 6i, 0.5i etc.|dw:1346674007860:dw|
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