how do u simplify x^3-8/x-2

Question

parthkohli · Answer

You simplify that by first simplifying $x^3 - 8$.

parthkohli · Answer

Remember:$$\large a^3 - b^3 \implies (a - b)(a^2 + ab + b^2)$$

parthkohli · Answer

Let's simplify it already. You have something in the form$$\large {a^3 - b^3 \over a - b} $$$$ \implies \large{ \cancel{( a - b)}(a^2 + ab + b^2) \over \cancel{a- b}}$$$$ \implies a^2 + ab + b^2$$Just find $a^2 + ab + b^2$ right here.

parthkohli · Answer

Let $a = x $ and $b = 2$.

parthkohli · Answer

If necessary, don't forget to include $x \ne 2$.

anonymous · Answer

try to use synthetic division

parthkohli · Answer

That'd make it very, very long.

parthkohli · Answer

But yeah you can use synthetic division

2 | 1   0   0   -8
   |
--------------

anonymous · Answer

@ParthKohli  that guy is offline..)))

parthkohli · Answer

2| 1   0   0  -8
  |
--------------
   1   2   4   0

lgbasallote · Answer

polynomial division is cooler

             x^2
          _____________________
x - 2 | x^3 + 0x^2 + 0x - 8
            x^3 - 2x^2
            =============
                        2x^2 + 0x

yada yada