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find the domain of the function f(x)=9/sqrt. x+5
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denominator cant be zero
ok its not
when is sqrt x + 5 zero?
f(x)=9/ sqrt. x+5
x+5 can't be negative
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yepp, that too
it is not negative i typed it the way it shows
this precalculus is hard
if you mean sqrt(x+5) then as i said previously there's no square root of a negative number since X can be any real number you need to excluse any X for which x+5 is negative
so for any x that's less or equal to -5 this function is not defined
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so my answer would be undefined
nah it 'd be \[(5,\infty)\]
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