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Mathematics 15 Online
OpenStudy (anonymous):

find the domain of the function f(x)=9/sqrt. x+5

OpenStudy (anonymous):

denominator cant be zero

OpenStudy (anonymous):

ok its not

OpenStudy (anonymous):

when is sqrt x + 5 zero?

OpenStudy (anonymous):

f(x)=9/ sqrt. x+5

OpenStudy (anonymous):

x+5 can't be negative

OpenStudy (anonymous):

yepp, that too

OpenStudy (anonymous):

it is not negative i typed it the way it shows

OpenStudy (anonymous):

this precalculus is hard

OpenStudy (anonymous):

if you mean sqrt(x+5) then as i said previously there's no square root of a negative number since X can be any real number you need to excluse any X for which x+5 is negative

OpenStudy (anonymous):

so for any x that's less or equal to -5 this function is not defined

OpenStudy (anonymous):

so my answer would be undefined

OpenStudy (anonymous):

nah it 'd be \[(5,\infty)\]

OpenStudy (anonymous):

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