Question

two structural members b and c are bolted to bracket a. knowing they're tension p=6kips and q=4kips, determine the magnitude and direction of the resultant force.

Answer 1

* their

Answer 2

Reference angles are with horizontal (x-axis) and translate to theta1=180-25=155 deg with the positive x-axis, and theta2=180+50=230 deg.

Sum forces in x and y direction:
\[\sum F_x\ = P \cos(\theta_1)+Q \cos(\theta_2)\]
\[\sum F_y\ = P \sin(\theta_1)+Q \sin(\theta_2)\]
The resultant can be calculated from the sums above.

Answer 3

i got fx: -6.07 ; fy: -7.70

Answer 4

I don't get the same numbers.
I have Fx=-8.009 and Fy=-0.528
Do you have P=6 kips and Q=4 kips.
Angle theta1=180-25 and angle theta2=180+50?

Answer 5

oops my calc was in a different mode. yep i got it, thanks!

Answer 6

Great!