Question

Find an exact solution to the equation below so that 0 < theta < pi/2.

1=sqrt(3)tan(2theta)

I know that I have to use the double angle formula for tan but I'm not positive what to do after that!
Any help is appreciated!

Answer 1

nah, cube the equation first

Answer 2

So
1=3tan(2theta)
1/3=tan(2theta)

Still running into the issue of double angle! (:

Answer 3

1/3=(2tanx)/(1-tan^2x)

Answer 4

Not sure what to do from there though.

Answer 5

where did the sqrt go??

Answer 6

Oh shoot haha I thought of it as a cube root.

Answer 7

Why cube it?

Answer 8

coz me toothought of it as a cube root.

Answer 9

whats the question. can u use the equation tab n write it?

Answer 10

\[1=\sqrt{3}\tan(2x)\]

Answer 11

1=√3tan(2x)

1/√3 = tan(2x)

2x = 30

x = 15

Answer 12

simple, lol

Answer 13

How did you get from the second step to the third?

Answer 14

and it should be in radians sorry. (theta)

Answer 15

oh,

then 2x = pi/6

Answer 16

15 degrees = pi/12 radians which is correct thank you.

Answer 17

welcome :D