Question

\[W(x) = {3z + 9 \over 2 - z} \]Find derivative.
Wait... solving it. Just want to check my answer.

Answer 1

I need no disturbance.
Note: I know that there's quotient rule in this, but please let me solve for a minute.

Answer 2

\[W'(x) = {(3z + 9)'(2 - z) - (3z + 9)(2 - z)' \over (2 - z)^2 } \]\[\implies \qquad {(6 - 3z) - (3z +9)(-1) \over (2 - z)^2} \]\[\implies \qquad {(6 - 3z) - (-3z - 9) \over (2 - z)^2} \]\[\implies \qquad {6 - 3z + 3z + 9 \over (2 - z)^2} \]\[ \implies \qquad{ 15 \over (2 - z)^2}\]

Answer 3

Am I correct?

Answer 4

Looks perfect to me.

Answer 5

Thank you, KingGeorge.