Question

An integer, 10 to 99, inclusive, is to be chosen at random. What is the probrability that the number chosen will have 3 as at least 1 of its digits?

1/10

1/5

1/9

1/3

9/10

Answer 1

The probability is:
\[
\frac{10+9-1}{90}
\](Because 03 is not a valid case).

Answer 2

hmmm...ok thnx. so solving that equation will give me the answer. i also may need to simplify it too

Answer 3

1/5