please help me solve this simultaneous equation.. x+2y=5 3x+2y=3
Subtract them, what will you get?
subtract what?
x+2y=5 (1) 3x+2y=3 (2) Subtract the first equation for the second one, of course!
i'm sorry i've never been taught this in school..its difficult for me to understand :/
No problem, I'm glad you speak it up so I know the right place to start :)
The way you subtract equation is go vertically Pretending x is candy, y is cookie
so 3x -x? or x-3x?
Either way is working, but in case you want 3x -x, then you need to switch the order of other terms, too!
i'll use x-3x then..would that mean -2x=-2
x=1 ???
If you want (1) \ (2), then: x-3x = -2x, 5 -3 = 2 -> -2x = 2
yes of course..so x=-1???
ok...now how do we find y?
Now, you has value x = -1, plug it back to any simpler equation => y
-1+2y=5 -1+5=6 6/2=3=y
Yupe, so you have the intersection point of 2 lines I ( -1, 3) :D
thank you sooo much..your a life saver :)
makes me feel much more confident thanks
thank you :)
Feel free to ask as many more as you like :)
i feel a bit cheeky but could you help me with this one please... 2x-4y=6 2x+y=8.5
Just open the new post, I'll follow up :)
Anyway since you notice both equations have the same 2x => Subtract them!
so 2x-2x? then 6-8.5 which would give x=-2.5?
Just open the new post, I'll follow up :)
Join our real-time social learning platform and learn together with your friends!