Question

lim of (x-2)/(x^2 -x-2) as x approaches 2??
idk how to solve limits...

Answer 1

first check that you get \(\frac{0}{0}\) when you replace \(x\) by \(2\)
you do
so

1) factor
2) cancel
2) replace \(x\) by 2

Answer 2

\[\frac{x-2}{x^2-x-2}=\frac{x-2}{(x-2)(x+1)}=\frac{1}{x+1}\] is the calculation
don't think too hard about how to factor, because you know if \(2\) gets you 0, then \(x-2\) must be a factor
now let \(x=2\)

Answer 3

then it's zero?

Answer 4

no

Answer 5

oh for the last one? 1/3?

Answer 6

yes

Answer 7

does thatmean that the limit is 1/3?

Answer 8

wait so is a limit always a y value

Answer 9

yes and yes