Question

An object moves along the x axis according to the equation x(t) = (2.90t2 - 2.00t + 3.00) m.
(a) Determine the average speed between t = 1.80 s and t = 3.00 s.
m/s

(b) Determine the instantaneous speed at t = 1.80 s and at t = 3.00 s.
m/s (t = 1.80)
m/s (t = 3.00)

(c) Determine the average acceleration between t = 1.80 s and t = 3.00 s.
m/s2

(d) Determine the instantaneous acceleration at t = 1.80 s and t = 3.00 s.
m/s2 (t = 1.80)
m/s2 (t = 3.00)

Answer 1

What´s is the entire question?

Answer 2

An object moves along the x axis according to the equation x(t) = (2.90t2 - 2.00t + 3.00) m.
(a) Determine the average speed between t = 1.80 s and t = 3.00 s.
m/s

(b) Determine the instantaneous speed at t = 1.80 s and at t = 3.00 s.
m/s (t = 1.80)
m/s (t = 3.00)

(c) Determine the average acceleration between t = 1.80 s and t = 3.00 s.
m/s2

(d) Determine the instantaneous acceleration at t = 1.80 s and t = 3.00 s.
m/s2 (t = 1.80)
m/s2 (t = 3.00)

Answer 3

what must i do with the given time values?

Answer 4

You must derivate.

Answer 5

The v(t) is simply the derrivative? How did you get m/s units of the derrivative?

Answer 6

also, so let me see if im understanding_ the first derrivative gives me the velocity and the second derrivative gives me the acceleration?

Answer 7

yes

Answer 8

Here it´s the letter A.

Answer 9

Here it´s the letter B.

Answer 10

Just plug the values t=1.80s and t=2.00 s in the equation and after use the formulae V

Answer 11

More help on the way