Question

find the derivative of 8y=3x^5-5Ox^3+135x

Answer 1

use power rule

\[\frac d{dx} (8y) \implies 8y^{\prime}\]
\[\frac d{dx} (3x^5) \implies 5 \times 3x^{5 - 1} \implies 15x^4\]
\[\frac d {dx} (50x^3) \implies 3 \times 50x^{3-1} \implies 150x^2\]
\[\frac d{dx} (135x) \implies 135\]
does that help?

Answer 2

i will use derivative of a quotient for that solution or not? please answer me.

Answer 3

quotient rule? no. this is purely power rule

Answer 4

although...you'll have to divide both sides by the coefficient of y' later on to isolate y'

Answer 5

thanks a lot. i'll try to solve it now. ^____^

Answer 6

@Igbasallote because i was ask to get the roots i got \[8y \prime=15(x^2-9)(x^2-1)\] will become \[8y \prime= 15 (x-3)(x+3)(x-1)(x+1)\] how can i get the roots if there is 8 in y'?

Answer 7

divide both sides by 8

Answer 8

only that step? so it will be disregarded if ever and the roots are 3, -3, 1, and -1.is that so?

Answer 9

pretty much. constant factors are always disregarded

Answer 10

thanks i get now

Answer 11

wonderful