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OpenStudy (anonymous):
subtract the fraction and reduce (x/(x^2-5x+6)) - (2/(x^2-4))
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OpenStudy (anonymous):
Can you factorize this one:
x^2-5x+6 = ...?
OpenStudy (anonymous):
(x-3) (x-2) and (x+2)(x-2)
OpenStudy (anonymous):
and i know you need like terms
OpenStudy (anonymous):
Great, so now you will have the common denominator is ( x+3) (x+2) ( x-2)
Can you continue?
OpenStudy (anonymous):
Actually
x^2-5x+6 = (x-3) (x+ 2)
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OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
i got an answer but apparently it was wrong i was hoping you could work it out so i could see where i went wrong.... my answer was
OpenStudy (anonymous):
Oop, hold on!
OpenStudy (anonymous):
Since common denominator is ( x-3) (x+2) ( x-2):
x (x-2) = x² - 2x
2 ( x-3) = 2x - 6
Subtract them:
-> (x² - 4x+ 6 ) / ( x-3) (x+2) ( x-2):
OpenStudy (anonymous):
and you can't factor the to[ right
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OpenStudy (anonymous):
top****
OpenStudy (anonymous):
That's final result!
OpenStudy (anonymous):
okay thank you
OpenStudy (anonymous):
So do you know where you're confused?
OpenStudy (anonymous):
yea i tryed to factor out the top and you can't do that thats why i go tit wrong
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OpenStudy (anonymous):
Because the top has Δ < 0, and the question doesn't mention about imaginary solution!
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