Question

(GEOMETRY QUESTION, PLEASE HELP!!!!) For the next 7 questions, let trapezoid GHIJ be inscribed in circle Q.

1. If the measure of arc HL equals 40 degrees calculate the measure of arc IO.?

2. If m 13 years ago

Answer 1

@lgbasallote @LolWolf

Answer 2

@eliassaab help? thanks!

Answer 3

@KingGeorge @Shi

Answer 4

lets begin wid few observations :

i) its an isosceles trap : HI || GJ , and , HG \(\cong\) IJ
ii) QL is perpendicular bisector of HI , and, GJ (cuz HI || GJ)

Answer 5

yes

Answer 6

any ideas for Q1 ?

Answer 7

I tried and got 140 degrees

Answer 8

1. If the measure of arc HL equals 40 degrees calculate the measure of arc IO.?
IO = LO - LI
= 180 - HL
= 180 - 40

Answer 9

Perfect !

Answer 10

great!

Answer 11

2. If m<GJI=78 degrees, calculate for m<GHI

Answer 12

they are congruent?

Answer 13

if you see, \(\angle GJI\) and \(\angle GHI\) are subtended by the same chord \(GI\)

so they are congruent !

Answer 14

how do i calculate for GHI now?

Answer 15

I got 102 degrees

Answer 16

GHI + HGJ = 180

GHI = 180 - HGJ
= 180 - GJI
= 180 - 78
= 102

Answer 17

for #3 I got 54?

Answer 18

i got 54 too.
you've used pythagoras or something else ?

Answer 19

pythagoras

Answer 20

#4 I got 60.

Answer 21

im still thinking hw to solve.. . LO

Answer 22

5. is the only one I really need now, I solved the others

Answer 23

Let the radius be r
then in ΔQLI
QL^2 + LI^2 = QI^2
(r-6)^2 + 18^2 = r^2
r = 30
So dia LO = 30*2 = 60

Answer 24

corret?

Answer 25

i dont see how \(\triangle\)QLI is right triangle,
lets get back to this later.

im working on #5 .. .

Answer 26

ok

Answer 27

arc length = \(\theta * radius\)

\(\theta = 156 * \frac{\pi}{189} \)

radius = ?

Answer 28

im stuck here... thats where you're also stuck right ?

Answer 29

yes!

Answer 30

you sure its not "arc measure" ?

cuz, arc length can be anything for a given angle

Answer 31

it is "measure" sorry many question, I ge jumbled with my words

Answer 32

central angle = 2*inscribed angle