Question

(x^2+x+6)(x-6)

Answer 1

multiply everything in the first parentheses by \(x\)
then multiply it all by \(-6\)
then combine like terms

Answer 2

i can walk you through it if you like

Answer 3

yes please!

Answer 4

ok so first i did x^2 times x and it still remained x^2 right

Answer 5

ok
\[(x^2+x+6)(x-6)\]multiply everything in first parentheses by \(x\) you get
\[x^3+x^2+6x\]
then multiply everything by \(-6\) you get
\[-6x^2-6x-36\] so as a start we have
\[x^3+x^2+6x-6x^2-6x-36\] and then we have to combine like terms

Answer 6

oh sorry i did not see your question'
no, \(x^2\times x=x^3\) not \(x^2\)

Answer 7

we can go even slower if you prefer

Answer 8

\[x^3-6x-36?\]

Answer 9

close

Answer 10

because when i combine like terms 6x -6x cancel out

Answer 11

yes that is true, there is no \(x\) term in the answer

Answer 12

there is an \(x^3\) term, and also a \(-36\) so that part is right, but \(-6x^2+x^2=-5x^2\)

Answer 13

ok what about -5x^2???

Answer 14

x^3-5x-36?

Answer 15

\[x^3+x^2+6x-6x^2-6x-36\]
\[=x^3+x^2-6x^2+6x-6x-36\]
\[=x^2-5x^2-36\]

Answer 16

yes, that one is right

Answer 17

yes! thank you

Answer 18

i trying to get the hang of it

Answer 19

but make sure you write \(-5x^2\) not \(-5x\)
when you combine like terms keep the exponent the same

Answer 20

a little practice and it will be easy
it is more or less like multiplying a two digit number by a three digit number

Answer 21

they said its not right

Answer 22

i typed x^2-5x^2-36

Answer 23

did you write
\[x^3-5x^2-36\]?

Answer 24

first term should be the \(x^3\) term

Answer 25

yes i got it

Answer 26

whew scared me for a moment

Answer 27

I was typing to fast i guess lol