Question

(2x+3h)^2 i started off with 4x^2 now im stuck

Answer 1

\[(2x+3h)^2=(2x+3h)(2x+3h)\] you have to do four multiplications

Answer 2

first one does give \(4x^2\)

Answer 3

16h^2

Answer 4

\[(2x+3h)(2x+3h)=2x\times 2x+2x\times 3h+2x\times 3h+3h\times 3h\] is a start

Answer 5

mostly you can skip some of that step, and go right to
\[4x^2+6xh+6xh+9h^2\]

Answer 6

4x^2+16h^2...i think im moving to fast and skipping steps

Answer 7

four multiplications, just like if you were going to multiply \(23\times 23\)

Answer 8

you have "middle terms" as well
it is not just squaring the first and last term

Answer 9

4x^2+12xh+9h^2 is what i got from your steps

Answer 10

that is correct

Answer 11

how about
\[23\times 23\] you would do
2 3
2 3
_____
6 9
4 6

four multiplications, then add
this is the same thing

Answer 12

only this time you have variables so you get \(4x^2+6xh+6xh+9h^2\) or
\(4x^2+12xh+9h^2\)

Answer 13

ok so i see my mistake i forgot my middle terms and thats how you got 12xh