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Please help, how do I find the inverse of this function!
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I would but I am in Honors Geometry Grade 9 not Calc.
\[y=\frac{e^x}{1+2e^x}\] solve for \(x\) or else write \[x=\frac{e^y}{1+2e^y}\] and solve for \(y\)
\[x=\frac{e^y}{1+2e^y}\] \[x(1+2e^y)=e^y\] \[x+2xe^y=e^y\] \[2xe^y-e^y=-x\] \[(2x-1)e^y=-x\] \[e^y=-\frac{x}{2x-1}\] whew
or if you prefer \(e^y=\frac{x}{1-2x}\) either way now to get \(y\) take the log
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@bkeith2698 thanks for trying
No problem @fall2012
@satellite73 , will y then be equal to \[-\log((2x-1)/-x)\]
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