A mathematics journal has accepted 14 articles for publication. However, due to budgetary restraints only 9 articles can be published this month. How many ways can the journal editor assemble 9 of the 14 articles for publication?

Question

erinweeks · Answer

A. 726,485,760 	
	B. 14 	
	C. 2,002 	
	D. 126

anonymous · Answer

you are being asked for how many ways to choose 9 out of a set of 14
in math this is called "14 choose 9"
the notation is $\dbinom{14}{9}$ and it is calculated via 
$$\dbinom{14}{9}=\frac{14\times 13\times 12\times 11\times 10}{5\times 4\times 3\times 2}$$ cancel first, multiply last 
you get 
$$14\times 13\times 11=2002$$

anonymous · Answer

many calculators have a key for that, or you can use this http://www.wolframalpha.com/input/?i=14+choose+9

erinweeks · Answer

well 2,002 is wrong :/i already used that answer and i got it wrong

mathmate · Answer

The question is not clear.
Assemble probably is meant to say order is important, which means the answer should be 14P9, or 726485760.

jim_thompson5910 · Answer

If order matters, then

n P r = (n!)/(n-r)!

14 P 9 = (14!)/(14-9)!

14 P 9 = (14!)/(5)!

14 P 9 = (14*13*12*11*10*9*8*7*6*5!)/(5)!

14 P 9 = 14*13*12*11*10*9*8*7*6

14 P 9 = 726,485,760

So if order matters, then there are 726,485,760 different ways

mathmate · Answer

14P9 = 14!/(14-9!