Find the domain and range of y = -3tan(3x+pi) +2
For this type of problems, it is best to first graph the "main" function, namely, \(\tan x\): http://i45.tinypic.com/35cn6m8.png You can immediately see that the range of the function stretches from \(-\infty\) to \(\infty\). The domain, however, stretches from \(-\infty\) to \(\infty\) as well, but leaves out the points \(k\pi/2\), for all integers \(k\). Because adding \(\pi\) to the function leads to an overlapping, left shift, we have that \(\tan(x)=\tan(x+\pi)\). Hence, the only change to the domain happens when you multiply \(x\) by \(3\): \(\tan(3x)\). This "halves" the frequency of the function's period by \(1/3\). If normally you have a domain of \(\mathbb{R}\setminus\{k\pi/2\}\), where \(k\in\mathbb{Z}\), can you figure out the new domain if we are now "halving" it by \(1/3\)?
kpi/6?
will I have to remember those limits on the domain and range for the future?
You're correct, and the only thing I'd suggest remembering is the period of the most common trigonometric functions.
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