In an x-ray tube, electrons are accelerated in a uniform electric field and then strike a metal target. Suppose an electron starting from rest is accelerated in a uniform electric field with 50. kV potential.
(a) What is the change in electrical potential energy of the electron?
(b) What is the change in kinetic energy of the electron?
(c) What is the final velocity of the electrons?
(d) If the 50. kV potential is generated by a uniform electric field over a 0.20 m distance, what is the electric field strength?
(e) What is the force on the electron due to the electric field?

Question

In an x-ray tube, electrons are accelerated in a uniform electric field and then strike a metal target. Suppose an electron starting from rest is accelerated in a uniform electric field with 50. kV potential.
(a) What is the change in electrical potential energy of the electron?
(b) What is the change in kinetic energy of the electron?
(c) What is the final velocity of the electrons?
(d) If the 50. kV potential is generated by a uniform electric field over a 0.20 m distance, what is the electric field strength?
(e) What is the force on the electron due to the electric field?

anonymous · Answer

1. change in p.e of the electron will be= charge*p.d.

anonymous · Answer

2. equate this change in pe with ke of e i.e. 1/2 m v^2...where m=mass of e and v=vel of e

anonymous · Answer

3.electric field strength will be p.d/ distance...

anonymous · Answer

what is pd

anonymous · Answer

pd is potential diff

anonymous · Answer

sorry...3rd is the answer of ur 4th Q

anonymous · Answer

u can calculate the final speed from change in k.E. which u will find out from Q 2.

anonymous · Answer

and force on the electron= charge*electric field strength

anonymous · Answer

wow  kind of hard to understand

anonymous · Answer

u got it...or want more explanation

anonymous · Answer

more explanation step by step please

anonymous · Answer

ok...start from part a

anonymous · Answer

i have answered it..tell me ur difficulty..

anonymous · Answer

change in p.e of the electron will be= charge*p.d

anonymous · Answer

change in potential energy of electron= charge of electron * potential difference

anonymous · Answer

what is the change. thats what what I do not get

anonymous · Answer

electron is starting from rest in a x-ray tube...it'll have some p.e. at that instant

anonymous · Answer

now it is accelerated through some PD....

anonymous · Answer

is it fie with u?

anonymous · Answer

fine*

anonymous · Answer

ok so the change is equal to the movement of the electron

anonymous · Answer

no...change in pe of the electron due to PD...n due to this PD...it'll accelerate

anonymous · Answer

ok...we take another example....suppose u have a stone...and u throw it vertically upward.

anonymous · Answer

suppose...stone has the zero potential energy at the ground

anonymous · Answer

what happens to the PE if u throw it up....

anonymous · Answer

it increses?

anonymous · Answer

yes...and what happens to kinetic energy?

anonymous · Answer

contrary to Pe?

anonymous · Answer

yes...it'll decrease

anonymous · Answer

so that is the change

anonymous · Answer

|dw:1346741071875:dw|