Question

Last complex fraction that I have to do! Please help :)

Answer 1

and here starts the race.....

Answer 2

lol wow

Answer 3

\[\frac{ 1 }{ x-3 }+4x=\frac{ 1+4x(x-3) }{ x-3 }=\frac{ 1+4x^2-12x }{ x-3 }\]

Answer 4

hope you can do rest of the calculation :)

Answer 5

yes i can! thank you! I just calculated it, and I got the answer: 5x-3/3(x-1)

Answer 6

shouldn't it be 3x??

Answer 7

check again!

Answer 8

\[\frac{ 4 }{ x }-\frac{ 1 }{ x-3 }= \frac{ 4(x-3)-x }{ x(x-3)}=\frac{ 4x-12-x }{ x^2-3x }=\frac{ 3x-12 }{ x^2-3x }\]

Answer 9

does that help?? @kakrazz ??/ and @hartnn dude..where's the pied piper ??

Answer 10

lol....u are helping na....

Answer 11

oh i see.... :)

Answer 12

okay! thanks :)

Answer 13

:) YW