Question

16Cn +16C9 =17C9

Answer 1

\[16Cn \implies \frac{16!}{n!(16-n)!}\]
\[16C9 \implies \frac{16!}{9!(16-9)!} \]
\[17C9 \implies \frac{17!}{9!(17-9)!}\]
does that help?

Answer 2

so how do you find n?

Answer 3

u know that property:
\[^nC_r+^nC_{r-1}=^{n+1}C_r\]
?

Answer 4

@virtus use this property, and put n=16,r=9
so now can u find your 'n' ??

Answer 5

oh i see, your job is to find \(n\) for thie equality correct?