x^4-y^4
-------
x^2+y^2

Question

x^4-y^4
-------
x^2+y^2

parthkohli · Answer

What you will do here is that, you will factor the numerator and cancel something from the denominator.

parthkohli · Answer

Keep in mind that $x^4 - y^4 = (x^2)^2 - (y^2)^2$ which is somewhat a difference of two perfect squares.

anonymous · Answer

could you give me the sol and answer

parthkohli · Answer

Not really... I am busy right now.

anonymous · Answer

ok
thanks anyway

anonymous · Answer

Suppose X = x², Y = y²
-->         X²  -     Y²   =  ...
@XDiesel Can you fill in where the .... is

anonymous · Answer

the what?

anonymous · Answer

i cant understand
you

anonymous · Answer

X² - Y²
because the variables are not the same.
i guess

mathmate · Answer

You can use the standard identity:
$$ a^2-b^2\ =\ (a+b)(a-b) $$
and recognize that
$$ x^4 - y^4 $$ can be written as $$ (x^2)^2 - (y^2)^2 $$

anonymous · Answer

nice
what is the final answer

mathmate · Answer

If you want to understand how to work out problems, this is the place. If you only want the answer, try: http://www.wolframalpha.com/ and type in your problem.

anonymous · Answer

thanks

mathmate · Answer

You're welcome! :)

anonymous · Answer

$$
\frac{x^4-y^4}{x^2+y^2}=\frac{\left(x^2-y^2\right)
   \left(x^2+y^2\right)}{x^2+y^2
   }=x^2-y^2
$$

parthkohli · Answer

Which could further be simplified, sir, to get $(x + y)(x - y)$