Question

x^4-y^4
-------
x^2+y^2

Answer 1

What you will do here is that, you will factor the numerator and cancel something from the denominator.

Answer 2

Keep in mind that \(x^4 - y^4 = (x^2)^2 - (y^2)^2\) which is somewhat a difference of two perfect squares.

Answer 3

could you give me the sol and answer

Answer 4

Not really... I am busy right now.

Answer 5

ok
thanks anyway

Answer 6

Suppose X = x², Y = y²
--> X² - Y² = ...
@XDiesel Can you fill in where the .... is

Answer 7

the what?

Answer 8

i cant understand
you

Answer 9

X² - Y²
because the variables are not the same.
i guess

Answer 10

You can use the standard identity:
\[ a^2-b^2\ =\ (a+b)(a-b) \]
and recognize that
\[ x^4 - y^4 \] can be written as \[ (x^2)^2 - (y^2)^2 \]

Answer 11

nice
what is the final answer

Answer 12

If you want to understand how to work out problems, this is the place.

If you only want the answer, try:
http://www.wolframalpha.com/
and type in your problem.

Answer 13

thanks

Answer 14

You're welcome! :)

Answer 15

\[
\frac{x^4-y^4}{x^2+y^2}=\frac{\left(x^2-y^2\right)
\left(x^2+y^2\right)}{x^2+y^2
}=x^2-y^2
\]

Answer 16

Which could further be simplified, sir, to get \((x + y)(x - y)\)