Question

PLEASE, HELP:

Answer 1

The first and third (i & k) components are fine.
There is a little error in the j-component.
What do you get for the indefinite integral?

Answer 2

\[ \large \int t\sqrt{t-2}\,dt=\frac{2t}{3}\cdot(t-2)^{3/2}-\frac{4}{15}
\cdot(t-2)^{5/2} \]

Answer 3

Is it the final answer?

Answer 4

as MATHMATE pointed out, your \(i\) and \(k\) components are correct. it is the \(j\) component that's wrong. what i posted is the indefinite integral of this component. u have to evaluate it on the interval [2,3]

Answer 5

@Nazyma ??

Answer 6

\[ \large \int_2^3 t\sqrt{t-2}\,dt=\left.\frac{2t}{3}\cdot(t-2)^{3/2}-\frac{4}{15}
\cdot(t-2)^{5/2}\right|_2^3=\frac{26}{15} \]