Question

Would this be the dimensional analysis of this equation?

F=m(V^2/R)
(kg)(m/s)^2=(kg)((m/s)^2/(m))
(kg)(m/s)^2=(kg)(m/s)^2
[F]=[MLT-2]?

did I do that dimensional analysis right....?

Answer 1

\[\frac{kg*m}{s^2}=\frac{kg\frac{m^2}{s^2}}{m}=\frac{kg*m^2}{s^2*m}=\frac{kg*m}{s^2}\]

Answer 2

? Can you draw that out.. It's all mumble jumble on my laptop.. I don't know why.