Question

I got this far and can't finish it: find the limit as x goes to zero of. Sin pi/6 (cos delta x) + cos pi/6 (sin delta x) - 1/2. All over delta x

Answer 1

Is this what you mean?\[\lim_{\Delta x\to0}\frac{\sin(\pi/6)\cos(\Delta x)+\cos(\pi/6)\sin(\Delta x)}{\Delta x}\]

Answer 2

Yeah sorry I'm new to this and dont know how to do that notation

Answer 3

you got that far, from where did you find that?

Answer 4

split the fraction into 2 parts\[\frac{a+b}{n}=\frac an+\frac bn\]

Answer 5

This is the original problem. Lim of delta x goes to zero of.
Sin (pi/6 + delta x ) + 1. All over Delta x

Answer 6

then you used the angle addition property and .. yeah

Answer 7

Uh u lost me there

Answer 8

i was just catching up to the part you already did; but still, you just need to split the fraction in two

Answer 9

Oh gotcha but then once the fractions are split what do you do. Can you divide by the delta x

Answer 10

you recall the definitions for:\[\lim_{h\to\ 0}\frac{sin~h}{h}\text{ and }\lim_{h\to\ 0}\frac{cos~h}{h}\]

Answer 11

the sin goes to 1; and the cos goes to 0

Answer 12

Oh duh yeah the lightbulb just went on. Thanks so much for being patient wi me

Answer 13

:) good luck