Question

-2m^2 + 8 / 7m^3 11m^2 - 4m + 5

Answer 1

can you rewrite this please?

Answer 2

use parenthesis

Answer 3

or draw it out

Answer 4

ok so this is the problem (-2m^2)+(8) / (7m^3)(11m62)-(4m)+5

Answer 5

ups sorry its (-2m^2)+8 / (7m^3)(11m^2)-(4m)+5

Answer 6

@timo86m i rewrote it

Answer 7

\[-2\,{m}^{2}+{\frac {8}{7}}\, \left( m \left( 11\,{m}^{2} \right) \right) ^{-3}-4\,m+5 \]

ok that last one this is what you mean?

Answer 8

no its \[-2m^2+8 / 7m^3-11m^2-4m+5 = 0\]

Answer 9

\[\frac{-2m^2+8} {(7m^3)(11m^2)-4m+5}\]
this?

Answer 10

yes exactly!

Answer 11

sooo what exactly is the question?

Answer 12

how to solve it

Answer 13

lol sorry cherry but i have a feeling me and that other guy knew that is what you meant all along :)

Answer 14

simplify it i guess

Answer 15

okay so the only part i need help with is the bottom \[7m^3-11m^2-4m+5\]

Answer 16

\[\frac{-2m^2 + 8 }{ 7m^3+ 11m^2 - 4m + 5}\]
\[-2(x^2-4)=-2(m+2)(m-2)\]
\[7m^3-11m^2-4m+5\]doesn't factor so there is nothing you can do with it

Answer 17

oooh equal to zero? then solve
\[(m+2)(m-2)=0\] because a fraction is only zero if the numerator is

Answer 18

yeah

Answer 19

so what about the bottom?