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Mathematics 9 Online
OpenStudy (anonymous):

Help with exponents? If I could just get help with one problem that I've worked on..

OpenStudy (anonymous):

OpenStudy (anonymous):

The first problem in that attachment is giving me a LOT of trouble.

OpenStudy (anonymous):

Multiply or divide as indicated. a ^ 5 ______ a I came up with a ^ 5 as the answer.

OpenStudy (anonymous):

1 2 and 5 are wrong

OpenStudy (anonymous):

Okay, thanks, could you help me with those?

OpenStudy (anonymous):

\[\frac{a^5}{a}=\frac{a*a^4}{a}\] does this help?

OpenStudy (anonymous):

Um, I still don't understand..

OpenStudy (anonymous):

\[\frac{a*a^4}{a}=\frac{a}{a}*a^4\] how about now?

OpenStudy (anonymous):

\[a^5=a*a*a*a*a\]

OpenStudy (anonymous):

Oh, so multiply the numerator and denominator to the power of 4?

OpenStudy (anonymous):

im not multiplying anything im just factoring it

OpenStudy (anonymous):

a number to an exponent "n"is the same as multiplying the number by itself n times ex.\[a^4=a*a*a*a\]\[x^2=x*x\]\[2^5=2*2*2*2*2\] and anything to an exponent of 0 is equal to 1 \[x^0=1\] \[9001^0=1\]

OpenStudy (anonymous):

when you divide exponents of like terms with each other, you subtract the bottom number from the top \[\frac{x^5}{x^2}=x^{5-2}=x^3\] \[\frac{3^{100}}{3^{99}}=3^{100-99}=3^1=3\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

if they arent like terms, then you cant do anything to them \[\frac{x^9}{y^9}\] leave them as is

OpenStudy (anonymous):

but wouldn't my problem just be x^5, because it is 5-0

OpenStudy (anonymous):

also remember \[x=x^1\] thus \[a=a^1\]

OpenStudy (anonymous):

oh, so it would be 5 - 1 = 4, making the answer x^4 ?

OpenStudy (anonymous):

if you have an exponent to another exponent, you multiply the 2 \[x^{3^2}=x^{3*2}=x^6\]

OpenStudy (anonymous):

yes the first answer would be a^4

OpenStudy (anonymous):

and you said my second answer was incorrect?

OpenStudy (anonymous):

is that one just 11a^-2 ?

OpenStudy (anonymous):

\[5a^2 *6a^4=5*a^2*6*a^4=5*6*a^2*a^4\] the exponent is correct, however you do not add the 5 and 6, you multiply them

OpenStudy (anonymous):

oh, 30a^-2 then

OpenStudy (anonymous):

when you multiply an exponent to another exponent, you add them\[a^4+a^2=a^{4+2}=a^6\] \[3^2*3^3=3^{2+3}=3^5\]

OpenStudy (anonymous):

i said the exponent was correct!!! and then you go and change it

OpenStudy (anonymous):

:( what do you mean? I never changed it...

OpenStudy (anonymous):

you got a^6 not a^-2

OpenStudy (anonymous):

so a^6 is the answer?

OpenStudy (anonymous):

no... 30a^6.........

OpenStudy (anonymous):

okay, okay.

OpenStudy (anonymous):

If you want to help my with the fifth one, I'd appreciate it..

OpenStudy (anonymous):

you should understand it by now it was the same concept as the first problem x=x^1 y=y^1

OpenStudy (anonymous):

type your answer and ill check it

OpenStudy (anonymous):

24b^3 c^4

OpenStudy (anonymous):

why the heck did you add 4 to 20, when you're obviously dividing

OpenStudy (anonymous):

exponent division= subtract the numbers exponent multiplications = add the numbers regular division is still division regular multiplication is still multiplication

OpenStudy (anonymous):

okay, I never got that...

OpenStudy (anonymous):

so thanks,

OpenStudy (anonymous):

so the 5 was correct, the exponents were wrong

OpenStudy (anonymous):

and your new answer was absolutely incorrect

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