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Find all the rational zeros of the function. C(x)= 2x^3 + 3x^2 -1
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your POSSIBLE zeroes are \[\pm 1\; , \; \pm \frac 12\] does that help?
I had gotten that far. But I tried synthetic division with all possible, and couldn't get any to work out right.
let me teach you the factor theorem pick one from 1, -1, 1/2 and -1/2 then substitute it to ALL the x in 2x^2 + 3x^2 - 1 find out which one gives you 0
Oh. With synthetic division, I had to add in a 0x, right?
yep
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Yeah, that was my problem. Thanks for the help!
welcome
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