Question

sqrt(48+sqrt(x))-4=4thsqrt(x) find x?

Answer 1

\[\sqrt{48+\sqrt{x}}-4=\sqrt[4]{x}\]

Answer 2

\[\sqrt{48+\sqrt{x}}-4=\sqrt[4]{x}\] like that?

Answer 3

yes

Answer 4

oh yes, i see it

Answer 5

guess you this is going to be annoying.
you are going to have to square both sides
then do it again

Answer 6

i don't get it ?

Answer 7

yeah i can see this is going to be a pain
square both sides
\[(\sqrt{48+\sqrt{x}}-4)^2=(\sqrt[4]{x})^2\]

Answer 8

ooh i see, and then i do another on

Answer 9

you get
\[48+\sqrt{x}-8\sqrt{48+\sqrt{x}}+16\sqrt{x}\]

Answer 10

actually you get
\[48+\sqrt{x}-8\sqrt{48+\sqrt{x}}+16=\sqrt{x}\]

Answer 11

we can cancel the \(\sqrt{x}\) from both sides
also \(48+16=64\) so we get
\[64-8\sqrt{48+\sqrt{x}}=0\]

Answer 12

subtract 64 from both sides
divide both sides by -8 and get
\[\sqrt{48+\sqrt{x}}=8\]

Answer 13

square again, and you should be in good shape
don't forget to check your answer because squaring could introduce and extraneous solution