Question

???

Answer 1

pay no attention to the denominator
multiply out and combine like terms in the numerator

Answer 2

\[3x\times 2x-(x^2+4)\times 3\]is what you need to work with

Answer 3

let me know what you get, it should not be too bad to work out

Answer 4

do i distribute the 3?

Answer 5

yes

Answer 6

and don't forget that big fat minus sign in front

Answer 7

6c-3x^2+12

Answer 8

oh

Answer 9

yeah you forgot it already

Answer 10

also i assume that mysterious \(6c\) was \(6x^2\)

Answer 11

6x-3x^2-12

Answer 12

careful
\[2x\times 3x=6x^2\] not \(6x\)

Answer 13

3x^2-12

Answer 14

that is the right one

Answer 15

you can factor out a 3 if you like, and write \(3(x^2-4)\) or even \(3(x+2)(x-2)\) but that is just showing off. i would leave it as \(3x^2-12\)

Answer 16

factor?

Answer 17

oh there you go haha

Answer 18

oh it does say "factored form" doesn't it

Answer 19

what about the bottom? can i factor that?

Answer 20

was it clear how to factor?

Answer 21

it does say to factor

Answer 22

no, the denominator is already in factored form
it is \((x^2+4)^2\)

Answer 23

that means \((x^2+4)(x^2+4)\) so it is already factored. leave it alone

Answer 24

alright so?

Answer 25

3(x+2)(x-2) for the top

Answer 26

yes i got it right

Answer 27

good

Answer 28

can you help me out with another one?

Answer 29

sure post in a new question and i will answer