Question

...

Answer 1

\[\frac{6x}{(x+1)(x-1)}-\frac{3}{(x+2)(x-1)}\] is a start
least common multiple of the denominators is therefore
\[(x+1)(x-1)(x+2)\]

Answer 2

ok

Answer 3

so now i multiply?

Answer 4

so first one you have to multiply top and bottom by \(x+2\) and second one you have to multiply top and bottom by \(x-1\) to put them over the same denominator, so you can subtract

Answer 5

\[\frac{6x(x+2)-3(x-1)}{(x+1)(x-1)(x+2)}\]

Answer 6

one again work only in the numerator
multiply out, don't forget the minus sign, then combine like terms

Answer 7

6x^2+12x-3x+3

Answer 8

6x^2+9x+3

Answer 9

i think that looks good, let me check

Answer 10

one question, why cant i cancel the (x+2) and (x-1) from the denominator and numerator? to end up with 6x-3/(x+1)?

Answer 11

yeah looks good
i guess you can once again factor
factor out the 3 at least

Answer 12

oooh don't do that it is a big mistake

Answer 13

you can only cancel factors
lets imagine you had to add up two regular fractions, say
\[\frac{2}{5}+\frac{3}{7}\] what would you do?
you would write
\[\frac{2\times 7+5\times 3}{5\times 7}\] now you cannot cancel the 7 and the 5 because they are not factors of the numerator

Answer 14

ooh makes sense

Answer 15

so to factor uhh i got 3(2x^2+3x+1) but that looks totally wrong and the frist try was 3x(2x+3 and then i cant get the rest because its wrong

Answer 16

i think it is right. lets see if we can go further.
usually these do not factor

Answer 17

the first one looks right? im trying to hurry up because its due in less that 15 minutes

Answer 18

oh yes we can factor
\[3(2x^2+3x+1)=3(2x+1)(x+1)\]

Answer 19

and NOW you can cancel

Answer 20

now can you cancel

Answer 21

oh yess!

Answer 22

lol yeah

Answer 23

ok so that would leave the answer right?

Answer 24

this usually does not happen
problem was cooked up to cancel
don't look to cancel first though

Answer 25

\[\frac{3(2x+1)}{(x-1)(x+2)}\] should be the final answer

Answer 26

no it says its wrong D:

Answer 27

hold on it is wrong

Answer 28

\[\frac{3(2x^2+3x-1)}{(x+1)(x-1)(x+2)}\]

Answer 29

my mistake at the beginning
should have been
\[\frac{6x(x+2)-3(x+1)}{(x+1)(x-1)(x+2)}\]

Answer 30

ok now it's right lol i ended up with an 88 percent :/

Answer 31

sorry
above answer is now correct
on line class?

Answer 32

oh no it's ok, its actually my fault for not doing my homework earlier and no it mathlabplus

Answer 33

we do our class homework there

Answer 34

it's*

Answer 35

well at least you are doing the homework
good luck

Answer 36

thank you, and thanks for your help :)

Answer 37

yw