consider the function f(x)=5x^2-17x+6 1. find f(x+h)
just plug in "x+h" for "x" expand and/or simplify as necessary
5*(x+h)^2 -17(x+h) +6
= 5*(x^2+ 2*x*h+ h^2) -17*(x+h) +6 and so on....
Thank you
sure:) that help? was there more to the problem?
yes for number 2 of the problem it says for h cannot equal 0, find f(x+h)-f(x)/h
yep, I thought so:)
so we found f(x+h) now let's add f(x) to it and simplify...
-f(x) I meant ...
5*(x^2+ 2*x*h+ h^2) -17*(x+h) +6 - ( 5x^2-17x+6 )
notice the 5*x^2 's cancel.... what else?
well just real quick, sorry. how did you get the -f(x) ?
just made the entirety of f(x) negative... (ie I put a minus sign in front of f(x) )
- ( 5x^2-17x+6 )
so -5*x^2 +17*x -6
oh, okay yest! i see it.
so simplify the rest and let me know what you get...
okay
so i got 2xh+h^2+17h. would i need to further break that down?
does it just stay in that format?
well remember, it was all over 'h' (we left that out while we were simplifying the numerator...)
so there's one more simplification to make... factor the h out of the numerator and h/h =1
looks like you forgot to multiply a few terms by the '5' too... go back and fix that...
2xh+h^2-85x-85h+30+17x-6/h can you tell me if so far i'm on the right path?
you're skipping steps or something
5*(x^2+ 2*x*h+ h^2) -17*(x+h) +6 - ( 5x^2-17x+6 )
do the first term on the left 5*(x^2+ 2*x*h+ h^2) = ?
5x^2+10xh+5h^2 ?
good:)
rest is pretty easy
-17x -17h +6 -5x^2 +17x -6
17x and 17x cancel 6 and -6 cancel all that's left is -17h and -5x^2
what you got from the first step : what I got from the 2nd: 5x^2+10xh+5h^2 -17h -5x^2
Is that the format I would leave it in? I wouldn't need to further break it down?
combine and you get 5h^2 +10xh -17h
then we need to put that all over h: (5h^2 +10xh -17h)/h = 5h +10x-17
Thank you so much. For some reason I was having such a stressful time with this problem and I kept coming up with answers that made no sense.
:) hope it helped!
it really did. thank you!
sure!
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