Question

How do u factor 2x^3+3x^2-8x-12

Answer 1

anyone have an answer?

Answer 2

or to (16n^4)-1

Answer 3

factored as well

Answer 4

x^2(2x+3)-4(2x+3)
you got the rest?

Answer 5

yep, thanks so much :)
btw, would you happen to know how to factor the second problem?

Answer 6

OH. okay. I hope this isn't wrong, because I get things wrong....a lot..

But use factor by grouping.

First group the 4 into 2 pairs, such as:
(2x^3+3x^2) + (-8x-12)
Factor these
x^2(2x+3) -4(2x+3)
Put together.
(x^2 -4) (2x+3)
You can still factor the first one, so:
(x-2)(x+2)(2x+3)

Answer 7

that looks great, thanks to both of you

Answer 8

anyone happen to know (16n^4)-1?

Answer 9

factored

Answer 10

((4n)^2-1^2)
remember (a^2-b^2) = (a-b)(a+b)

Answer 11

so first step
(((4n)^2)^2-1^2) = ((4n)^2-1)((4n)^2+1)
second sterp hint
you can do it again with (4n)^2-1

Answer 12

thanks for the assistance, i deeply appreciate it