can someone show me how to find the domain and range of these two equations please 1) f(x)= sqrtx^2-5x+6 2) f(x)= |2x+1|-3
Domain: The set of x-s where the computation is ALLOWED, recall now that Square root is only allowed where the expression inside it is NON-negative
What is the expression inside root in THIS case ?
x must be a negative number
Range: the set of y-s you "hit" by computing the function on ALL possibly allowed x-s (on the domain that is)
Isn't it \[\sqrt{x^2 -5x +6}\]
yes
Sooo you have instead to solve\[x^2-5x +6 \ge 0\]
Faaaind the roots, graph the parabola - start solving the inequality
if i knew hoe to do that i wouldn't have asked the question
oops i mean how to do that
Look up : SOlving quadratic Equations. then Look up: quadratic inequalities Believe me its better to start catching up NOW instead of plastering-over until later
May be drawing the graph and finding the domain and range would be easier.
no solving algabraiclly would be more easier
Drawing the graph of\[y= \sqrt{x^2 -5x +6}\] WITHOUT solving for roots ? Hmmm doubtful to say the least....
|dw:1346829557055:dw| |2x+1|-3
domain and range for that = -3.infinity
now for the other one
israel you want to have a go at it
for the graph I drew above the domain is R range is -3 to infinity
now for the other one....
|dw:1346830032579:dw|
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