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Mathematics 15 Online
OpenStudy (anonymous):

can someone show me how to find the domain and range of these two equations please 1) f(x)= sqrtx^2-5x+6 2) f(x)= |2x+1|-3

OpenStudy (anonymous):

Domain: The set of x-s where the computation is ALLOWED, recall now that Square root is only allowed where the expression inside it is NON-negative

OpenStudy (anonymous):

What is the expression inside root in THIS case ?

OpenStudy (anonymous):

x must be a negative number

OpenStudy (anonymous):

Range: the set of y-s you "hit" by computing the function on ALL possibly allowed x-s (on the domain that is)

OpenStudy (anonymous):

Isn't it \[\sqrt{x^2 -5x +6}\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Sooo you have instead to solve\[x^2-5x +6 \ge 0\]

OpenStudy (anonymous):

Faaaind the roots, graph the parabola - start solving the inequality

OpenStudy (anonymous):

if i knew hoe to do that i wouldn't have asked the question

OpenStudy (anonymous):

oops i mean how to do that

OpenStudy (anonymous):

Look up : SOlving quadratic Equations. then Look up: quadratic inequalities Believe me its better to start catching up NOW instead of plastering-over until later

OpenStudy (anonymous):

May be drawing the graph and finding the domain and range would be easier.

OpenStudy (anonymous):

no solving algabraiclly would be more easier

OpenStudy (anonymous):

Drawing the graph of\[y= \sqrt{x^2 -5x +6}\] WITHOUT solving for roots ? Hmmm doubtful to say the least....

OpenStudy (anonymous):

|dw:1346829557055:dw| |2x+1|-3

OpenStudy (anonymous):

domain and range for that = -3.infinity

OpenStudy (anonymous):

now for the other one

OpenStudy (anonymous):

israel you want to have a go at it

OpenStudy (anonymous):

for the graph I drew above the domain is R range is -3 to infinity

OpenStudy (anonymous):

now for the other one....

OpenStudy (anonymous):

|dw:1346830032579:dw|

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