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The body of mass 5kg has a momentum of 10kgm/s.When a force of 0.2 N is applied in a direction for 10 sec,the change in Kinetic Energy is?
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\[p=mv\] hence,v=2....now\[F \delta t=impulse\]impulse=change in momemtum=2,as mass is constant,change in velocity is 2.\[kinetic energy=1/2 mv^2\].use these eq. to find the answer.
The answer I get is 10.Actually From whatever formula I calculated,the answer came 10,but it was not among the options for this MCQ. The options were something like 3.5,3.8,3.2 and 4.4J I don't remember the figures Exactly but I'm pretty sure they were in 3s and 4s
use the above methord...u ll gt ur ans.
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